Nitrogen is 1s22s22p3
Add: 1s22s22p3 N : 2, 5 . . . . N . . .
1s22s22p3. Adding the exponents gives a sum of 7, which is the total number of electrons a C- ion has. Follow a diagonal rule chart and they should become easy.
Aufbau says that the sublevels fill 1s2, 2s2, 2p6. That would mean that you must have filled 1 and 2 s (=4) and 3 more. Last I checked, 3 + 4 = 7. Which element has 7 electrons? I'll give you a hint: its atomic number is 7. Another hint: its symbol is N.
If you mean 1s22s22p3, you would refer to the periodic table. Using 2p3, you would look at the second period (row), look at the p block, and count 3 elements to the right to find nitrogen.
Nitrogen is 1s22s22p3
It is 1s22s22p3
I think it is: 1s22s22p3
Add: 1s22s22p3 N : 2, 5 . . . . N . . .
3 The electron configuration for nitrogen is 1s22s22p3.
1s22s22p3. Adding the exponents gives a sum of 7, which is the total number of electrons a C- ion has. Follow a diagonal rule chart and they should become easy.
Aufbau says that the sublevels fill 1s2, 2s2, 2p6. That would mean that you must have filled 1 and 2 s (=4) and 3 more. Last I checked, 3 + 4 = 7. Which element has 7 electrons? I'll give you a hint: its atomic number is 7. Another hint: its symbol is N.
If you mean 1s22s22p3, you would refer to the periodic table. Using 2p3, you would look at the second period (row), look at the p block, and count 3 elements to the right to find nitrogen.
1s22s22p3
Only 8 groups present in periodic table. Group1,2,3,4,5,7,0 Stealth 1991
The shorthand electron configuration allows all of the electrons in a noble gas preceding an element to be omitting and written by [nobel gas name]. For nitrogen, the noble gas preceding it is He. Thus, its configuration is [He]2s2 2p3.
There are three bonds between Nitrogen and hydrogen and there are thus 3 shared bonding pairs of electrons. in addition since Nitrogen is 1s22s22p3 there are also the none bonding 1s2 electrons and the 2s2 electrons making 5 total shared pairs of electrons.