two of hydrogen and one of oxygen is water
You probably mean H2SO4, where H +1; S +6;O-2.H2SiO4 does not exist. If it did the oxidation numbers of the constituent elements would be H +1; Si +6; O -2. The compound silicic acid is H4SiO4 (not isolatable) with H +1, Si +4 and O -2.
[ h(+1+1)=o(-2) ]= [ h(+2)o(-2) ] =h2o
You do this For EX: _HCl + _MgO -> _H2O + _MgCl2 Mg-1 H-2 Coefficient O-1 Mg-1 | H-1 Cl-1 V Cl-1 O-1 EX: 2HCl + MgO -> H2O + MgCl2 Mg-1 H-2 O-1 Mg-1 H-2 -- Cl-2 Cl-2 --Mark out O-1 out and replace And then your done....
To form water (H₂O), the balanced chemical reaction is 2 H₂ + O₂ → 2 H₂O. This indicates that 2 moles of hydrogen gas (H₂) are required to produce 2 moles of water (H₂O). Therefore, for 8.12 moles of H₂O, you would need 8.12 moles of H₂, as the ratio of H₂ to H₂O is 1:1.
The decomposition of hydrogen peroxide (H₂O₂) can be represented by the balanced equation: 2 H₂O₂ → 2 H₂O + O₂. From this equation, we see that 2 moles of H₂O₂ produce 1 mole of O₂. Thus, the decomposition of 5.43 moles of H₂O₂ will yield 5.43 mol H₂O₂ × (1 mol O₂ / 2 mol H₂O₂) = 2.715 moles of O₂. Therefore, 2.715 moles of oxygen gas will result from the decomposition of 5.43 moles of hydrogen peroxide.
It is 1:2:1
It is 1:2:1
The oxidation number of potassium (K) is +1, hydrogen (H) is +1, phosphorus (P) can vary but in K2HPO4, it is +5, and oxygen (O) is -2. Therefore, the oxidation number of K2HPO4 is +1 for K, + 1 for H, +5 for P, and -2 for O.
2 heads are better than one
2 H and 1 O combine valence electrons to become stable.
This molecule is formaldehyde.
2