Cinderella has 2 Ugly Sisters
If you mean a circle inscribed in the square: C = circumference, π = pi, r = radius, s = side, P = perimeter C = 2πr r = s/2 C = πs s = P/4 C = πP/4 So for this problem, the circumference is 9π, or about 28.3 If you mean a square inscribed in the circle, the computations are practically the same, except: r = sqrt(2)s/2 C = sqrt(2)πs C = sqrt(2)πP/4 So for this problem, the circumference is sqrt(2)9π, or about 40.0
1. A quantum number assigned to baryons and mesons, equal to b + s where b is the baryon and s is the strangeness. 2. A quantum number equal to b + s+ c where the c is the charm.
2 All Beef Patties, Special Sauce, Lettuce, Cheese, (Pickles, Onions) on a Sesame Seed Bun
C. P. D. r a i a c n p k o p e s y d a u r s (sponsered by shreck 2 productions)
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
2 sides on a coin.
The answer depends on what information you do have.Suppose you know only the lengths of the sides (a, b and c), then let s = (a + b + c)/2.Then area = sqrt[s*(s - a)*(s - b)*(s - c)]If 2 sides and the included angle, then area = 1/2*a*b*sin(C).There are other formulae.
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
I have a pair of frog earings with the s/s and circled c on it ehat does it mean.
If you mean C = 5h-2 then C = (5*12)-2 => 58
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