FeCl3 + 3NaOh >>>>> Fe(OH)3 + 3NaCl
Iron(III) hydroxide is obtained. FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl I should say
Sodium borate forms Boric acid's precipitates in aqueous solution when reacts with Hydrochloric acid. Na3BO3 + 3HCl = H3BO3 + 3NaCl
3Na(s) + AlCl3(aq) -> 3NaCl(aq) + Al(s) This chemical formula is already balanced. You can check by looking at the number of each atom you have on each side. On the left hand side you have 3 Sodium, 1 Aluminium and 3 Chlorine atoms. On the right side you have 3 Sodium, 3 Chlorine and 1 Aluminium atoms. Therefore, it is balanced.
FeCl3 + 3NaOh >>>>> Fe(OH)3 + 3NaCl
Assuming double displacement. FeCl3 + 3NaNO2 --> Fe(NO2)3 + 3NaCl
Iron(III) hydroxide is obtained. FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl I should say
AlCl3+ 3NaOH = Al(OH)3+ 3NaCl
Sodium borate forms Boric acid's precipitates in aqueous solution when reacts with Hydrochloric acid. Na3BO3 + 3HCl = H3BO3 + 3NaCl
3Na(s) + AlCl3(aq) -> 3NaCl(aq) + Al(s) This chemical formula is already balanced. You can check by looking at the number of each atom you have on each side. On the left hand side you have 3 Sodium, 1 Aluminium and 3 Chlorine atoms. On the right side you have 3 Sodium, 3 Chlorine and 1 Aluminium atoms. Therefore, it is balanced.
Reaction_of_ferric_chloride_to_sodium_hydroxideBasically: FeCl3 (ferric chloride) + 3NaOH (sodium hydroxide) > Fe(OH)3 + 3NaCl (ferric hydroxide precipitate and sodium chloride, respectively)
Three moles of Na^+ ions. 3NaCl = 3Na^+ & 3Cl^-
It is a test when we put ferric chloride in a slightly alkaline solution check for the presence of acetate (CH3COO) 3CH3COOH + FeCl3 + 3NaOH ----------> Fe(CH3COOH)3 + 3NaCl + 3 H2O
Sodium is more reactive than aluminium no displacement reaction would be expected. The displacement reaction would be written as :- Al + 3NaCl= AlCl3+3Na)
By definition, a precipitate is not water soluble. It precipitates out of solution from its constituent ions by way of a double-replacement reaction. Example: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(s) The iron(III) hydroxide is the precipitate.