Iron(III) hydroxide is obtained.
FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
The reaction of FeSO4 (iron(II) sulfate) with K3PO4 (potassium phosphate) results in the formation of Fe3(PO4)2 (iron(II) phosphate) and K2SO4 (potassium sulfate).
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
The ionic equation for the reaction between nitric acid (HNO3) and iron (Fe) is: 3H+ + Fe -> Fe3+ + 3/2H2 This equation represents the dissociation of nitric acid into H+ ions and the oxidation of iron to Fe3+ ions.
The reaction between FeBr2 and H3PO4 will not produce a single product. Instead, it will result in a series of chemical reactions leading to various products depending on the reaction conditions. FeBr2 can react with H3PO4 to form different iron phosphate compounds and hydrogen bromide gas.
Fe3+ + 3OH- _____> Fe(OH)3
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
FeCl3
The reaction between iron (II) chloride and sodium phosphate results in the formation of iron (II) phosphate and sodium chloride. The balanced chemical equation for this reaction is: FeCl2 + Na3PO4 → Fe3(PO4)2 + 6NaCl.
The reaction of FeSO4 (iron(II) sulfate) with K3PO4 (potassium phosphate) results in the formation of Fe3(PO4)2 (iron(II) phosphate) and K2SO4 (potassium sulfate).
Fe + 3AgNO3 ==> Fe(NO3)3 plus 3Ag The oxidation number of Ag in AgNO3 (on the left side) is 1+ and in Ag (on the right side), it is zero. Thus, in this reaction, silver (Ag) has been reduced.
b. Fe3 plus ions
The ionic equation for the reaction between nitric acid (HNO3) and iron (Fe) is: 3H+ + Fe -> Fe3+ + 3/2H2 This equation represents the dissociation of nitric acid into H+ ions and the oxidation of iron to Fe3+ ions.
To separate Fe3+ ions, one can use a reagent like ammonia (NH3) which forms a complex with Fe3+ ions called iron(III) hydroxide. This complex precipitates out of the solution, allowing for the separation of Fe3+ ions from other components in the mixture.
The reaction between FeBr2 and H3PO4 will not produce a single product. Instead, it will result in a series of chemical reactions leading to various products depending on the reaction conditions. FeBr2 can react with H3PO4 to form different iron phosphate compounds and hydrogen bromide gas.
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
Fe(OH)3 is plain old rust. It is made when iron reacts with water and oxygen. Its called electrochemical corrosion: Cathode reaction: O2 + 2H2O + 4e- --> 4OH- Anode reaction: Fe --> Fe3+ + 3e- Fe3+ + 3OH- --> Fe(OH)3