hpo42
Formula: HPO42-
monohydrogen phosphate
PO43-
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-
PO43-
PO43- (phosphate) is the conjugate base of HPO42- (monohydrogen phosphate)
A polyprotic acid can (in a multi-step reaction) donate more than one proton per molecule of acid.E.g. phosphoric acid can do 'the trick' three times:H3PO4 --> H+ + H2PO4-H2PO4- --> H+ + HPO42-HPO42- --> H+ + PO43-
NaH2PO4(aq) + H2OàH3PO4(aq) + NaOH(aq) H3PO4(aq)ßàH+(aq) + H2PO4_(aq) H2PO4-(aq)ßàH+(aq) + HPO42-(aq) HPO42-(aq)ßàH+(aq) + PO43-(aq)
HPO42- is the most abundant phosphate present at pH=7.5, but H2PO42- is also there in (less) significant amounts. PO43- and H3PO4 are practically absent at pH 7.5.This is because it is between the valuespH=pKa,3= 12.4 (at which value there is 50% HPO42- and 50% PO43-) andpH=pKa,2= 7.2 (at which value there is 50% HPO42- + 50% H2PO42-)[Cf. Related links: A graph of "The phosphate presency"]
HPO4 does not exist. HPO42- would be the dibasic form of phosphoric acid and be the hydrogen phosphate ion. H3PO4 also exists and is phophoric acid. So if two moles of NaOH were reacted with phosphoric acid 2Na+ HPO42- would be formed disodium hydrogen phosphate.
H= +1 P= +5 O= -2 Source: Mastering Chemistry