Pb + CrCl2 = PbCl2 + Cr
considered a redox single replacement and the Cr has a +2 charge so we assume the Pb also has a +2 because it is a transition metal
The yield is 82,45 %.
You will get Pb(OH)4
I suppose it would be BaF2 + Cl2.
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The yield is 82,45 %.
Pb + PbO2 + H2SO4 --> PbSO4 + H2O
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
a peanut buter and jelly or jam sandwich
You will get Pb(OH)4
2 PbO + C -> 2 Pb + CO2
NI(NO3)3+pbbr4nibr3+pb(no3)4
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.
Lead (II)
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No. Hydrogen reacts with oxygen to yield water.