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This word stand for Line1 <<>> On electrical equipment the terminal L1 is where the placement of the supply conductor is terminated. On three phase equipment, the terminals are identified as L1, L2 and L3. On an electrical magnetic contactor these terminals will be located on the top of the device. The terminations on the bottom of the device where the load is connected are designated T1 and again for a three phase equipment the designation would be T1, T2 and T3.
P1/t1=p2/t2
q=c(T2-T1)
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]
Q=mcT T1 = (59.4-13.4)°C = 46°C (water)->46 K m1 = 1.93 kg c = 4180 J/(kg x K) T2 = (13.4-0)°C = 13.4°C (ice)->13.4 K m2 = ? Q1=Q2 m1 c T1=m2 c T2 m2= (m1 c T1) / (c T2) = (m1 T1) / T2 = 6.63 kg
On a schematic for an electronic circuit it usually means a transformer. T1 is the 1st transformer, T2 is the second etc. Some ferrite core wire wound inductors with more than one winding may be designated as T1.
On a schematic for an electronic circuit it usually means a transformer. T1 is the 1st transformer, T2 is the second etc. Some ferrite core wire wound inductors with more than one winding may be designated as T1.
COF = h1-h4/h2-h1=T1(s1-s4)/T2-T1(s1-s4)=T1/T2-T1
T1 and T2 can refer to the Thoracic vertebrae (part of your spine). But I don't know what 'low' would imply.
T1 and T2 refer to the first and second thoraxic vertebrae. They are the 8th and 9th vertebrae, starting from the top.
The CalDigit Thunderbolt™ T1 and T2 primarily differ in that the T1 is a single-drive solution whereas the T2 is a dual-drive solution. See related links for more information.
The SHLD (Store H&L Direct) instruction takes 5 machine cycles and 16 clock states, not including any wait states. Opcode fetch: T1, T2, T3, and TX Low order address fetch: T1, T2, T3 High order address fetch: T1, T2, T3 Store L: T1, T2, T3 Store H: T1, T2, T3
for the rxn A ---> B, where A is at temp T1 and B at temp T2 1) At constant pressure H1= HB - HA A first converts to B at temp T1 and reh temp rises to T2, thus the heat supplied for this change is Cp(T2-T1), Cp is the heat capacity of products. Hence the heat change will be given by H(path1)= Cp(T2-T1)+H1 2) first the temp of A is raised to T2. the heat supplied for this change is Cp'(T2-T1) , Cp' is the heat capacity of reactants. now A is changed to B with an enthalapy change of H2. H(path2)= Cp'(T2-T1)+H2. H(path1)=H(path2) H2-H1/T2-T1=Cp-Cp'
t1:german tiger 1 t2:german tiger 2 t1:armor 69 t2:armor 89 t1:speed 14 mph t2:speed 20 mph t1:gun is 98% great t2:gun is 99% good so german tiger 2 is better
This question refers to the combined gas law: (P1V1)/T1=(P2V2)/T2, where P is pressure, V is volume, and T is temperature in Kelvins.To solve for T1, rearrange the equation to isolate T1.T1=(P1V1T2)/(P2V2)
T1= Fat- Appears Bright e.g. Grey matter = Water- Appears Dark e.g. CSF, water T2 Just opposite to T1
Assuming the recursive definition is tn = 2*tn-1 t1 = 3 t2 = 2*t1 = 2*3 = 6 t3 = 2*t2 = 2*6 = 12 t4 = 2*t3 = 2*12 = 24