These are called "state symbols". In chemical equations, they tell us what form the compounds/elements etc. are present in: * (s) tells us that the substance is solid, such as 'CaCO3(s)' * (l) tells us that the substance is liquid or molten, such as 'H2O(l)' * (g) tells us that the substance is gaseous, such as 'CO2(g)' * (aq) tells us that the substance is in solution ie. aquaeous, such as 'HCl(aq)'
They are the state symbols in a chemical reaction. s = solid l = (pure) liquid g = gas aq = aqueous ( water) solution.
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
Yes, calcium carbonate will react with hydrochloric acid to form calcium chloride, water, and carbon dioxide. The ionic equation is: CaCO3(s) + 2H+(aq) -> Ca2+(aq) + H2O(l) + CO2(g). The net ionic equation is: CO3^2-(aq) + 2H+(aq) -> H2O(l) + CO2(g).
The answer is sol.
Out of these possible answers A) Ba(NO3)2(aq) + K2SO4(aq) -> BaSO4(s) + 2KNO3(aq) B) HCl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l) C) MgO(s) + H2)(l) -> Mg(OH)2(s) D) 2SO2(g) + O2(g) -> 2 SO3(g) E) 2H2O(l) -> 2H2(g) + O2(g)
They are the state symbols in a chemical reaction. s = solid l = (pure) liquid g = gas aq = aqueous ( water) solution.
3Cl2(g) + 6OH-(aq) --> ClO3-(aq) + 5Cl-(aq) + 3H2O(l)
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
Yes, calcium carbonate will react with hydrochloric acid to form calcium chloride, water, and carbon dioxide. The ionic equation is: CaCO3(s) + 2H+(aq) -> Ca2+(aq) + H2O(l) + CO2(g). The net ionic equation is: CO3^2-(aq) + 2H+(aq) -> H2O(l) + CO2(g).
This is not a decomposition reaction.
CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2CO3(aq) is the balanced chemical equation H2CO3 is not stable in this form, so it splits into CO2(g) + H2O(l) Therefore the true equation will be: CaCO2(s) + 2HCl(aq) -> CaCl2(aq) + CO2(g) + H2O(l) You NIE will start like this: CaCO2(s) + 2H+(aq) + 2Cl-(aq) -> Ca2+(aq) + 2Cl-(aq) + CO2(g) + H2O(l) and will end as: 2H+(aq) + CaCO2(s) -> Ca2+(aq) + CO2(g) + H2O(l)
K2Cr2O7(aq) + 3SO2(g) + H2SO4(aq) Cr2(SO4)3(aq) + K2SO4(aq) + H2O(l)
___NaOH(aq)+___CuSO4(aq)=>___CaO(s)+___H2O(l)=>___H___Al(s)+____O2(g)=>____BaCl2(aq)+____Na2SO4(aq)____CH4(g)+___O2(g)=>____CaCO3(s)+_heat _=>___HCl(aq)+___Zn(s)=>___Cl2(g)+__KBr(aq)=>
The answer is sol.
Cu(s) + 4H^+(aq) + 4NO3^-(aq) ==>Cu^2+(aq) + 2NO3^-(aq) + 2NO2(g) + 2H2O(l)
The equation with proper punctuation is A(s) + B(l) = C(g) + D(aq)where the chemicals (elements or compounds) are identified as follows:A and B are reactants - A is a (s)olid, and B is a (l)iquid.C and D are products - C is a (g)as and D is an (aq)ueous solution (in water)
L. G. Whitby has written: 'Multiple choice questions on clinical chemistry' -- subject(s): Clinical chemistry, Problems, exercises