This is not a decomposition reaction.
2H2,g + O2,g --> H2Ol
Please provide more information/context/clarification to help us answer this question. You can post your response in this answer text by clicking "Edit."
To determine the base dissociation constant (Kb) for the reaction involving ch33naq, h2ol, ch33nh, and oh-aq, you need the specific equilibrium expression related to the bases and their respective concentrations in solution. Without additional context or specific reaction details, the Kb value cannot be accurately calculated or provided. Generally, Kb values are determined experimentally or found in literature for specific bases.
The reaction is: CaO(s) + H2O(l)--- --> Ca(OH)2(s) Ca(OH)2(s) is the product (at the right side of the reaction equation).
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3
2H2,g + O2,g --> H2Ol
It means that it is in a liquid state as opposed to solid (ice) or gas (water vapour or steam)
Please provide more information/context/clarification to help us answer this question. You can post your response in this answer text by clicking "Edit."
To determine the base dissociation constant (Kb) for the reaction involving ch33naq, h2ol, ch33nh, and oh-aq, you need the specific equilibrium expression related to the bases and their respective concentrations in solution. Without additional context or specific reaction details, the Kb value cannot be accurately calculated or provided. Generally, Kb values are determined experimentally or found in literature for specific bases.
If it's in the form H2O(l) then the l stands for liquid. This is to show that liquid water is different than gaseous water (steam), which would be H2O(g) with a g for gas.
The reaction is: CaO(s) + H2O(l)--- --> Ca(OH)2(s) Ca(OH)2(s) is the product (at the right side of the reaction equation).
The heat of combustion can be calculated by subtracting the sum of the standard enthalpies of formation of the reactants from the sum of the standard enthalpies of formation of the products. For the combustion of C3H6 (propene) to CO2 and H2O, the heat of combustion would be calculated as follows: Heat of combustion = [(-394 kJ/mol) + (-285.8 kJ/mol)] - 20.6 kJ/mol = -660.4 kJ/mol.
6.6 x 10-9
Acetic acid + Sodium Bicarbonate ----> Sodium Acetate + Water + Carbon Dioxide CH3COOH + NaHCO3 ----> NaCH3COO + H2O + CO2
Melting
When carbon dioxide in exhaled air mixes with water, it forms carbonic acid. This reaction lowers the pH of the water, making it more acidic. This is the basis for the process of ocean acidification, which can have harmful effects on marine life.
2NaOHaq + 2HClaq --> 2NaClaq + H2Ol is the perfect balanced equatiion,except the solubility (aq) of NaCl, so it is notNaCls but NaClaq