To determine the base dissociation constant (Kb) for the reaction involving ch33naq, h2ol, ch33nh, and oh-aq, you need the specific equilibrium expression related to the bases and their respective concentrations in solution. Without additional context or specific reaction details, the Kb value cannot be accurately calculated or provided. Generally, Kb values are determined experimentally or found in literature for specific bases.
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
Barium chloride and sodium sulfate Molecular equation: BaCl2(aq) + Na2SO4(aq)--> BaSO4(s) + 2NaCl(aq) ionic equation: Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + SO4-2(aq) --> BaSO4(s) + 2Na+(aq) + 2Cl-(aq) Net ionic equation is Ba+2(aq) + SO4-2(aq) --> BaSO4(s)
A precipitate
aq bhoola
Mg(s) + H2SO4(aq) ==> MgSO4(aq) + H2(g) ... molecular equationMg(s) + 2H+(aq) + SO4^2-(aq) ==> Mg^2+(aq) + SO4^2-(aq) + H2(g) ... ionic equationMg(s) + 2H^+(aq) ==> Mg^2+(aq) + H2(g) ... net ionic equationSpectator is SO4^2- (sulfate ion).
Yes, calcium carbonate will react with hydrochloric acid to form calcium chloride, water, and carbon dioxide. The ionic equation is: CaCO3(s) + 2H+(aq) -> Ca2+(aq) + H2O(l) + CO2(g). The net ionic equation is: CO3^2-(aq) + 2H+(aq) -> H2O(l) + CO2(g).
6.6 x 10-9
2NaOHaq + 2HClaq --> 2NaClaq + H2Ol is the perfect balanced equatiion,except the solubility (aq) of NaCl, so it is notNaCls but NaClaq
Acetic acid + Sodium Bicarbonate ----> Sodium Acetate + Water + Carbon Dioxide CH3COOH + NaHCO3 ----> NaCH3COO + H2O + CO2
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
Molecular Eq HC2H3O2(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq) Ionic Eq H+(aq) + C2H3O2-(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq) Net Ionic Eq H+(aq) + NH3(aq) -> NH4+(aq)
Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION
NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq) KOH(aq) + HCl(aq) → KCl(aq) + H2O(l) Pb(NO3)2(aq) + KI(aq) → PbI2(s) + KNO3(aq) BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq) H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l)
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
The ionic equation for the reaction is: Fe^2+(aq) + CO3^2-(aq) -> FeCO3(s) and 2Na^+(aq) + 2Cl^-(aq) -> 2NaCl(aq).
The net ionic equation for the reaction between KCl(aq) and Pb(NO3)2(aq) to form KNO3(aq) and PbCl2(s) is: 2K^+(aq) + 2NO3^-(aq) + Pb^2+(aq) + 2Cl^-(aq) -> 2K^+(aq) + 2NO3^-(aq) + PbCl2(s)