The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
HNO3 + KOH ----> KNO3 + H2O This is the complete equation this is the net ionic equation. Because it is a strong acid (HNO3) and a strong base (KOH) it will always be H+ + OH- -------> H2O
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
HNO3 + KOH ----> KNO3 + H2O This is the complete equation this is the net ionic equation. Because it is a strong acid (HNO3) and a strong base (KOH) it will always be H+ + OH- -------> H2O
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
H+(aq)+OH−(aq)→H2O(l)
The net ionic equation for the reaction between HCHO2 (formic acid) and KOH (potassium hydroxide) is HCHO2 + OH- --> HCO2- + H2O. This equation shows the formation of formate ion and water from the reaction of formic acid with hydroxide ion in potassium hydroxide.
Answer this question… OH- + 2H+ 2H2O(l)
The net ionic equation is: Ca2+ (aq) + 2Ag+ (aq) → Ca2+ (aq) + 2Ag (s)
CH3COOH + KOH = CH3COOK + H2O
Ca2+(aq) + SO42-(aq)- --> CaSO4(s) is the net ionic equation.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).