HNO3 + KOH ----> KNO3 + H2O
This is the complete equation
this is the net ionic equation. Because it is a strong acid (HNO3) and a strong base (KOH) it will always be
H+ + OH- -------> H2O
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∙ 14y agoThe net ionic equation for the reaction of nitric acid (HNO3) and potassium hydroxide (KOH) is: H+ (aq) + OH- (aq) -> H2O(l)
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∙ 15y ago2K+2HNO3=2KNO3+H2. supposed to be like that
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∙ 14y agoOH-(aq) + H+(aq) => H2O(l)
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∙ 14y ago2Na + 2HNO3 = 2NaNO3 + H2
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∙ 14y agokh2so6
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The total equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O This reaction forms potassium nitrate (KNO3) and water (H2O) as products.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).
KOH(aq) + HNO3(aq) -> KNO3(aq) + H2O(l) This balanced ionic equation represents the neutralization reaction between potassium hydroxide (KOH) solution and nitric acid (HNO3), forming potassium nitrate (KNO3) and water (H2O).
The equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O where potassium nitrate (KNO3) and water (H2O) are formed.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The total equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O This reaction forms potassium nitrate (KNO3) and water (H2O) as products.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).
KOH(aq) + HNO3(aq) -> KNO3(aq) + H2O(l) This balanced ionic equation represents the neutralization reaction between potassium hydroxide (KOH) solution and nitric acid (HNO3), forming potassium nitrate (KNO3) and water (H2O).
The equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O where potassium nitrate (KNO3) and water (H2O) are formed.
The reaction between nitric acid (HNO3) and potassium hydroxide (KOH) results in the formation of potassium nitrate (KNO3) and water. The balanced chemical equation for this reaction is: HNO3 + KOH → KNO3 + H2O.
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is: 2KOH + HNO3 → KNO3 + H2O
When nitric acid (HNO3) reacts with potassium hydroxide (KOH), it forms potassium nitrate (KNO3) and water. The balanced chemical equation for this reaction is: HNO3 + KOH → KNO3 + H2O
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
For the reaction between HNO3 (acid) and KOH (base), it is a 1:1 molar ratio reaction. This means that 1 mole of HNO3 will react with 1 mole of KOH. So, 1 mole of KOH is required to neutralize 1 mole of HNO3 in this reaction.
Potassium hydroxide (KOH) will react with nitric acid (HNO3) in a neutralization reaction to form potassium nitrate (KNO3) and water (H2O). The balanced chemical equation for this reaction is: KOH + HNO3 -> KNO3 + H2O
HNO3 + KOH -----> KNO3 + H2O