HP- + H2O(l) ⇌ P2-(aq) + H3O+(aq)
HC2H3O2(aq) + KOH(aq) -> H2O(l) + KC2H3O2(aq)It's already balanced, since there are two acetates, two Hydrogens on each side, and 1 oxygen on both sides :)
The net ionic equation for the reaction between HCHO2 (formic acid) and KOH (potassium hydroxide) is HCHO2 + OH- --> HCO2- + H2O. This equation shows the formation of formate ion and water from the reaction of formic acid with hydroxide ion in potassium hydroxide.
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
The products of this reaction are potassium oxalate and water.
HC2H3O2(aq) + KOH(aq) -> H2O(l) + KC2H3O2(aq)It's already balanced, since there are two acetates, two Hydrogens on each side, and 1 oxygen on both sides :)
The net ionic equation for the reaction between HCHO2 (formic acid) and KOH (potassium hydroxide) is HCHO2 + OH- --> HCO2- + H2O. This equation shows the formation of formate ion and water from the reaction of formic acid with hydroxide ion in potassium hydroxide.
C_2_H_4_O_2_ (aq) + OH^-^ (aq) --> C_2_H_3_O_2_^-^ (aq) + H_2_O (l)
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
The products of this reaction are potassium oxalate and water.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
HNO3 + KOH ----> KNO3 + H2O This is the complete equation this is the net ionic equation. Because it is a strong acid (HNO3) and a strong base (KOH) it will always be H+ + OH- -------> H2O
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The eqnet ionic equation is HCN + OH- --> H2O + CN-
Balanced :2 K + 2 H2O ----> 2 KOH + H2
Plus 1 charge
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3