Displacement divided by time will give you the motion of an object that has no unbalanced force acting on it
It's as simple as total displacement divided by total time. Be careful though. If this is a velocity problem, displacement does not always equal distance.
That's a peculiar question. I'd call that the 'effective average speed', or the 'apparent average speed'.
Ifk
Average Velocity
no
Velocity is displacement/time.
a=dv/dt average velocity = displacement divided by time take. so average velocity = displacement/time taken.
displacement+time divided by distance
Every time the unicycle returns to its starting point, the average velocity equals zero. C. The total displacement divided by the time.
The Average Velocity on a position time graph or a velocity time graph.
The total displacement divided by the time. The slope of the displacement vs. time graph.
The slope of the ant's displacement vs. time graph The total displacement divided by the time.