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take g = 10 m/s^2 , u = 0 in all cases ,measured from same datum

s=(10*t^2)/2

if t = 1 second then s = 5 metres

if t = 2 seconds then s = 20 metres (2* time = 4*distance)

if t = 3 seconds then s = 45 meters (3* time = 9*distance)

if t = 4 seconds then s = 80 meters (4* time = 16 * distance)

but distance travelled between

secs metres

0-1.......5

1-2.... 15

2-3.... 25

3-4..... 35

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Q: What does doubling the falling time of something affected by gravity do in terms of distance?
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