take g = 10 m/s^2 , u = 0 in all cases ,measured from same datum
s=(10*t^2)/2
if t = 1 second then s = 5 metres
if t = 2 seconds then s = 20 metres (2* time = 4*distance)
if t = 3 seconds then s = 45 meters (3* time = 9*distance)
if t = 4 seconds then s = 80 meters (4* time = 16 * distance)
but distance travelled between
secs metres
0-1.......5
1-2.... 15
2-3.... 25
3-4..... 35
Now, this is in very....basic. It also may not be 100% correct. The higher up you are, the more distance you fall. The more distance you fall, the faster you go. You peak at a certain speed, and will continue falling at that speed once it is reached. The max speed differs in the amount of weight falling. (Proven by an Egg falling, or a Feather falling.)
bowling ball
you divide distance over time
In case of feely falling body
ask a teacher
The sound of something falling in another room would typically include a thud or a bump, depending on the weight and material of the object. The intensity of the sound may be muffled by walls and distance.
If the leaves were falling down
A feather.
Speed = distance / time.
Now, this is in very....basic. It also may not be 100% correct. The higher up you are, the more distance you fall. The more distance you fall, the faster you go. You peak at a certain speed, and will continue falling at that speed once it is reached. The max speed differs in the amount of weight falling. (Proven by an Egg falling, or a Feather falling.)
The falling action for the third wish is something
you have to figure it out c'mon.... i know your better than that
bowling ball
It does continue falling, until it runs into something that stops it, like the ground.
Let's imagine there is no air resistance and that gravity is the only thing affecting a falling object. Such an object would then be in free fall. Freely falling objects are affected only by gravity
you divide distance over time
In case of feely falling body