It means that you won't clot if you cut yourself.
Yes it can. I got Idiopathic thrombocytopenic and my was 0. Usually anything under 5 you can bleed out spontaneously even without a cut.
#include<stdio.h> #include<conio.h> void main() { int a[10],i,j,k; int count=1,num[10],pos=0; clrscr(); printf("Enter the Array Element "); for(i=0;i<10;i++) { scanf("%d",&a[i]) ; }//close the for loop for(i=0;i<10;i++) { count=1,pos++; for(j=0;j<10;j++) { if(a[i]==a[j]) { for(k=j;k<10;j++) a[k]=a[k+1] }//close the if count++; }//close the for loop num[pos] = count; }//close the for loop for(i=0;i<pos;i++) printf("Repeted Number of IN Arrary %d",num[i]); }//close the main
Count from 20 to 0.
IU/ml normal is between 0 - 12.5
Count by fives if is 0:05 or 0:00. If is 0:07 add 3 and then count by 5. If is 0:06 then add 4 then count by 5. If is 0:08 then add 1 and then count by 5. If is 0:09 then add 1 and count by 5. If is 0:04 then add 6 and count by 5. If is 0:03 then add 7 and count by 5. If is 2 add 8 and count by 5. If is 1 add 9 and count by 5.
Count by fives if is 0:05 or 0:00. If is 0:07 add 3 and then count by 5. If is 0:06 then add 4 then count by 5. If is 0:08 then add 1 and then count by 5. If is 0:09 then add 1 and count by 5. If is 0:04 then add 6 and count by 5. If is 0:03 then add 7 and count by 5. If is 2 add 8 and count by 5. If is 1 add 9 and count by 5.
0000000000000000000000000000000000000000000 0
It takes nine flip flops to count from 0 to 511.
0 seconds 0 minutes and 0 hours
Mean Sum/Count = 836/12 = 69.66... recurring.
int nearPalin(int n){ int temp = n; int count = 0; while(temp>0){ temp /= 10; count++; } if(count%2 == 0){ count = count/2; while(count--) n = n / 10; temp = n; while(n>0){ temp = temp*10 + n%10; n = n/10; } return temp; } else{ count = count/2; while(count--) n = n / 10; temp = n; n = n/10; while(n>0){ temp = temp*10 + n%10; n = n/10; } return temp; } }
Repeatedly divide by the base until the number is 0, counting the number of divisions as you go. int count_digits (int n, int base=10) { // default to decimal notation if (base<2) {/* handle invalid argument */} int count=0; while (n!=0) { n/=base; ++count; } return count; } Note that the value 0 has no digits. If you wish to count 0 as a digit, alter the algorithm as follows: int count_digits (int n, int base=10) { // default to decimal notation if (base<2) {/* handle invalid argument */} int count=0; do { n/=base; ++count; } while (n!=0); return count; }