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Helium (He) is one such element. So is Argon (Ar). There are probably others as well.
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
Atomicity is the number of atoms which constitute one molecule of an element. Simply we can say that it is the number of atoms of an element present in one molecule of that element.
the chemical element with atomic number 2, and is represented by the symbol He
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
Helium (He) is one such element. So is Argon (Ar). There are probably others as well.
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
From Wikipedia (which, should you use - say - Google, would have provided a quick and cheap answer):Magnesium (pronounced /mægˈniːziəm/) is a chemical element with the symbol Mg, atomic number 12, atomic weight 24.3050 and common oxidation number +2.-matt
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7
The atomic number is equal to the number of protons and neutrons in a neutral atom.
You mean the smallest particle of an element that still retains that element's properties. It is the atom. Even one atom of, say, carbon is still carbon. Cut it up any further and you no longer have carbon.
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
All atoms of the same element contain the same number of protons and electrons, but atoms of a given element may have different numbers of neutrons. Atoms with the same number of protons but different numbers of neutrons are called isotopes. An element has many isotopes--each with a close, but different number of neutrons.
Atomicity is the number of atoms which constitute one molecule of an element. Simply we can say that it is the number of atoms of an element present in one molecule of that element.
They change with atomic number.
This element (more correct in this case is isotope) doesn't suffer a radioactive disintegration.