Probably 20 millivolts above zero voltage. A really weak voltage.
My guess is 5'b10000 = 20mV 4'b1000 should be 10 mV (half of the previous one.) 5'b10000 + 4'b1000 = 5'b11000 20mV + 10mV = 30mV Is this correct?
The term "20mV" refers to a measurement of voltage, specifically 20 millivolts. In electrical terms, a millivolt is one-thousandth of a volt (1 mV = 0.001 V). This level of voltage is often used in various applications, such as in electronics, sensors, and signal processing, to indicate small electrical signals or to measure small changes in voltage.
feel positive
is a positive change
positive
Some assumptions have to be made. If you assume the left most bit is the highest order bit then 10000 = 16 decimal and 11000 = 24 decimal. Then if you assume a linear analog voltage output 20mV / 16 = XmV / 24 so X = (20 x 24)/16 = 30mV.
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Well, honey, the voltage generated by the thermocouple is directly proportional to the temperature difference. So, if the temperature range is 500 degrees Fahrenheit (1250 - 750), and the voltage range is 30mV (50 - 20), you can calculate the voltage generated at 1000 degrees Fahrenheit using a simple proportion. Just plug in the numbers and you'll get your answer, darling.
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Any number greater than 0 or it is positive.
strong and positive