R stands for the resistance.
R= Resistor
R = r*L/A where: R = resistance r = material resistivity L = length A = area Since you are doubling the diameter, you are increasing the area by a factor of 4, so Y will have 1/4 the resistance of X.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
22ma. E=R/I
Put the resistor symbol ie zig zag. Then put a crossing line with arrow headed at the top.
You just stated that the voltage across the resistor is 15 volts, so that's your answer ! If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts. The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.
resistor-thermistor
p=I*I*R ,P=V*V/R;where I is the current passing through the resistor, and V is the voltage across resistor, and R is the Resistance of the resistor,
the R stands for Resistor. It is a resistor plug.
it's generally the resistance. its generally the energy dissipiating component called Resistor
what does resistor mean in technolagy
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
R = r*L/A where: R = resistance r = material resistivity L = length A = area Since you are doubling the diameter, you are increasing the area by a factor of 4, so Y will have 1/4 the resistance of X.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
Resistor Relay
Resistor
It depends what you mean by your question. Ohms Law is the key. Power in a resistor is wasted as heat. If a resistor has 1 volt across it and passes a current of 1 amp, it will consume/dissipate one Watt of power ,and must therefore have a resistance of one ohm. To work out the power rating of a resistor required, use V x I = P V is voltage I is current in Amps P is power in Watts R is resistance in ohms V=I X R. I=V/R R=V/I Ohms Law is the fundamental equation of electricity and must be understood before you can go further.
It's a code to tell you the value of the resistance of the resistor.