M1 in Singapore has data plan specials from time to time.
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
rib cage
rib
Only When I Laugh - 1979 Adam's Rib 3-3 is rated/received certificates of: Australia:G UK:PG (video rating) (2008)
#include#includevoid main(){float avg(int m1,int m2,int m3);clrscr();printf("\nAverage of 3 Subjects: %.2f",avg(78,85,95));getch();}float avg(int m1,int m2,int m3){return (m1+m2+m3)/3;}
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
3.. hor-rib-ly
One sixth of the original : Force = (mass) x (acceleration). So Acceleration = (Force)/(mass).So A1 = F1/m1 ; if F2 = .5*F1 and m2 = 3*m1. So A2 = F2/m2 = (.5*F1)/(3*m1) = (F1/m1)/6 = A1/6.
-Algorithm- 1.START 2.Take m1 and m2 as integer matrix. 3.Input the values for original matrix and store it in m1. 4.Convert each row of the matrix ma in to column of matrix m2. 5.Display both matrix m1 and m2. 6.STOP. 'C' program #include<stdio.h> void main() { int m1[3][3],m2[3][3]; int i,j; for (i=0;i<3;i++) { for(j=0;j<3;j++) { printf("\n Enter value of%d rows and %d cols: ",i+1,j+1); scanf("%d",&m1[i][j]); } } for(i=0;i<3;i++); { for(j=0;j<3;j++) { m2[j][i]=m1[i][j]; } } printf("\n Original Matrix"); printf("\n ---------------\n"); for(i=0;i<3;i++) { for(j=0;j<3;j++) { printf("%d\t",m1[i][j]); } printf("\n") ; } printf("\n Transpose Matrix"); printf("\n ----------------\n"); for(i=0;i<3;i++) { for(j=0;j<3;j++) { print("%d\t",m2[i][j]); } printf("\n") }
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
dr/dt=(-64/5)(G^3/c^5)(m1*m2)((m1+m2)/r^3) t=r^4*[15*5/(64*16*4)]*[(c^5/G^3)/(m1*m2(m1+m2))] => t = (60*10^3)^4*(75/4096)*((3*10^8)^5/((6.673*10^-11)^3)/((1.4*1.989*10^30)^2*(2*1.4*1.989*10^30)) => t = (6)^4*(75/4096)*((3)^5/((6.673)^3)/((1.4*1.989)^2*(2*1.4*1.989))*10^(16+40+33-60-30)