"Tan y groes" is a Welsh phrase that translates to "under the cross" in English. It refers to a place, often a chapel or a graveyard, located near a cross.
In Spanish, "se siente tan bien" translates to "it feels so good" and "te quiero" translates to "I love you." So, the phrase "se siente tan bien y te quiero" means "it feels so good and I love you."
"Usted es tan perfecta" translates to "You are so perfect" in English.
"Estoy tan solo" in Spanish means "I am so alone" in English. It conveys a feeling of loneliness or isolation.
"Tan tierno" means "so tender" or "so sweet" in Spanish. It is often used to describe someone who is gentle, kind, or affectionate.
"Y el tiempo" is Spanish for "and the time."
"Y Groes Newydd"?
At the bottem groes plants
Do you mean sugar? That groes on a cane!
Sine sum identity: sin (x + y) = (sin x)(cos y) + (cos x)(sin y)Sine difference identity: sin (x - y) = (sin x)(cos y) - (cos x)(sin y)Cosine sum identity: cos (x + y) = (cos x)(cos y) - (sin x)(sin y)Cosine difference identity: cos (x - y) = (cos x)(cos y) + (sin x)(sin y)Tangent sum identity: tan (x + y) = [(tan x) + (tan y)]/[1 - (tan x)(tan y)]Tangent difference identity: tan (x - y) = [(tan x) - (tan y)]/[1 + (tan x)(tan y)]
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
double x, y; ... x = tan (y);
It groes
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
tan y = 20/15
There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
You find the smallest positive value y such that tan(x + y) = tan(x) for all x.