The amount of energy required to turn a mole of a liquid into a gas
The latent heat of evaporation
The amount of energy required to turn a mole of a liquid into a gas
The latent heat of vaporization of water is 2260 joules per kilogram.
The amount of energy required to turn a mole of a liquid into a gas
The latent heat of vaporization is what is commonly referred to as boiling. This is the amount of energy require to change from a state of liquid to vapor.
The energy required to boil a substance
Vaporization is the change of liquid water to water vapor. Vaporization requires addition of the latent heat of vaporization to liquid water. The latent heat of vaporization supplies the liquid water molecules with enough energy to become vapor molecules. The latent heat of vaporization at 1.0 atmosphere pressure is about 1000 Btu per lbm ( 2260 kJ per kg ).
Perspiration coats the outside of the skin with moisture (water). The water evaporates. Evaporation requires heat to be absorbed by the water (the latent heat of vaporization). Heat is removed from the body surface to provide the water with the latent heat of vaporization.
Because the latent heat of fusion and latent heat of vaporization are very high
The latent heat of vaporisation of water requires more energy. This is because on melting, the intermolecular bonds in water are only weakened whereas on boiling, the bonds are completely broken, which requires a larger amount of energy.
L can either mean the latent heat of vaporization or condensation. The latent heat of vaporization is the energy required to completely turn 1 kilogram of a liquid into a gas at its boiling point. The latent heat of condensation is the energy required to completely turn 1 kilogram of a solid into a liquid at its melting point.
Latent Heat of Evaporation, or Evaporation Enthalpy. It is given in units of energy over unit of mass, i.e., KJ/Kg.