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p and q represent the frequencies of two types of alleles.
The Hardy-Weinberg equation is as follows: p2 + 2pq + q2 = 1 p & q represent the frequencies for each allele.
p and q
The Q is the recessive trait and the P is the dominant trait. Always find Q first when solving Hardy Weinberg equations.
p^2 + 2pq + q^2 = 1
allele frequencies in a population will remain constant unless one or more factors cause those frequencies to change
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
If you have the alleles A and a, then the The hardy-weinberg equation is: A2 + 2Aa + a2 = 1 where a and A represent allele frequencies. So A2 would be the genotype frequency for AA. 2Aa is the genotype frequency for Aa. And a2 is the genotype frequency for aa. Plug in whatever information you have into the equation and you can probably come up with an answer. Save
Q-meter works on the principle of Series Resonance
formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency
The Hardy Weinberg equation is: p2 + 2pq + q2 = 1 Where p and q are the initial frequencies for the two alleles in question. This equation suggests that the three possible genotypes (homozygous p, heterozygous pq, and homozygous q) will reach a frequency equilibrium (i.e. stable frequency) in those proportions described above, if the following conditions are met: # Large population # No mutation # No selection# No emigration/immigration # Random mating In other words, evolution-- allelic frequency change within a population-- will not occur if the above 5 conditions are met.