The Q is the recessive trait and the P is the dominant trait. Always find Q first when solving Hardy Weinberg equations.
The frequency of the homozoygous recessive genotype
Emotional Quotient.
It stands for a quail bird
IQIA stands for I include Q question I in A answer
On a prescription if it says take 1 Q D S it usually means take 1 tablet 4 times a day
Q CAR is a reference to the Q SHIP used in World War 1 & 2. Essentially they were a decoy Royal Navy ship posing as a merchant ship used to trick German U -Boats. Unmarked police cars, mainly highway patrol vehicles use this term as they're covert appearance is designed to hide the fact they are in service of her Majesty (like the Q SHIP). The Q originally stood for Quiet, although some people believe it stands for "Queen's Car".
p and q
The Hardy-Weinberg equation is as follows: p2 + 2pq + q2 = 1 p & q represent the frequencies for each allele.
p and q represent the frequencies of two types of alleles.
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
Marvin Rosenblum has written: 'Topics in Hardy classes and univalent functions' -- subject(s): Univalent functions, Hardy classes 'On the operator equation BX-XA=Q' -- subject(s): Functional analysis
Depends on the equation. If it is similar to: Q = m*Cp*dT then Q = energy if it is similar to A= Ao * exp (-Q/RT) then Q is the activation energy
If you are interested in genotype as opposed to phenotype use the Hardy-Weinburg equation. q (squared) + 2qp + p (squared) = 1.0. Where q is represents the recessive allele and p is the dominant allele. If you know the number of homozygous recessive individuals in a population you can calculate for q and determine p using the equation q+p=1 If the number of recessive individuals in a population is .25 this equals q(squared) so q=.5 and p=.5 .25+.5+.25=1 This means that 50% of all the alleles for this trait are recessvie and 50% are dominant. If .36 of the population is homozygous recessive then q=.6 and p=.4 and the Hardy-Weinberg equation shows .36+2[(.6)(.4)]+.16=1=.36+.48+.16 To get percentage multiply by 100.
p^2 + 2pq + q^2 = 1
Why don't you express the equation verbally? Q 12 89 doesn't have much meaning.
Q - 12 = 89 Add 12 to both sides of the equation. Q - 12 + 12 = 89 + 12 Q = 101
The Hardy Weinberg equation is: p2 + 2pq + q2 = 1 Where p and q are the initial frequencies for the two alleles in question. This equation suggests that the three possible genotypes (homozygous p, heterozygous pq, and homozygous q) will reach a frequency equilibrium (i.e. stable frequency) in those proportions described above, if the following conditions are met: # Large population # No mutation # No selection# No emigration/immigration # Random mating In other words, evolution-- allelic frequency change within a population-- will not occur if the above 5 conditions are met.
cuz it looks like a q