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Answered 2009-12-16 19:00:46
It equals an undefined entity. The average acceleration of an object equals the CHANGE in velocity divided by the time interval. The term "change in velocity" is not the same as the term "velocity", "average velocity", or "instantaneous velocity".
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Change in velocity divided by time is acceleration, but velocity divided by time has no particular significance.
velocity divided by the time interval
At a small time interval, the average velocity is approximately equal to the instantaneous velocity. However, the values of the average velocity and the instantaneous velocity approach each other , as the length of the time interval is decreased more and more.
No. Acceleration is (change of velocity) divided by (time interval in which it changed). If velocity doesn't change, then there is no acceleration.
A body has uniform velocity if it covers equal displacement in equal intervals of time however short the interval may be.
Divided by time.Average acceleration is (change in velocity) / (time interval) Instantaneous acceleration is calculated by making the time interval very small. This is written as dv/dt.
a=dv/dt average velocity = displacement divided by time take. so average velocity = displacement/time taken.
No, It is the average velocity.
A change in velocity over a time interval is called an acceleration if the velocity is increasing, or a decelleration if the velocity is decreasing.
when a body travels unequal displacement in equal interval of time or visa-versa, it is said to have non-uniform velocity
Velocity is equal to the change in distance divided by the change in time. Speed is the magnitude of velocity
Yes acceleration equals velocity divided by time i.e a=v/t and it's S.I unit is m/s2
It is acceleration. The difference between final velocity and initial velocity, divided by the time is the AVERAGE acceleration. Remember, though that velocity is a vector. So if you are going round in a circle at a constant speed, your direction of motion is changing continuously and so you are always accelerating!
Instantaneous velocity is the velocity in difference displacement in shortest time or specific time interval.
Average velocity is change in position (displacement) divided by the interval.
It is not possible because the average velocity is equal to the displacement in a given time interval, ie: V = (displacement) / (time interval) As the zero displacement average speed will also be zero.
Yes, but only if the instantaneous velocity remains zero during the time inerval. If you are speaking of average velocity over an interval, all bets are off.
Average velocity in a direction is calculated as the displacement in that direction divided by the total time taken. As the time interval is reduced, the displacement over that period also reduces and the limiting value of that ratio is the instantaneous velocity.
The instantaneous velocity is the limit of the average velocity, as the time interval tends to zero. If you are not familiar with limits, basically you make the time interval very small and calculate the average velocity.
Velocity is equal to distance divided by time.
distance divided by velocity will give time
speed is distance divided by time Miles per hour velocity is distance divided by time for a given direction so it is direction sometimes known as a vector. so VECTOR
That would be speed, or if it's in a specific direction, velocity.
If acceleration is positive then velocity goes on increasing by equal amount in equal intervals of time, however small the interval may be If the same acceleration is negative then velocity goes on decreasing as described above
The velocity of an object (v) at any particular instant is the distance covered by that object (s) divided by the time interval (t) taken to cover the distance. When the velocity is changing, the instantaneous velocity is the distance covered in a very, very short time divided by the very, very short period taken to cover it. In differential calculus, this would be denoted by v = ds/dt By definition, then, s is the integral of v with respect to time. Graphically, this is the area under the velocity-time graph.
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