it will improve the power factor... The angle between voltage and current will decrease depends on capacitor value.
inductive load does not allow the current to become zero eve though the supply source get removed . inductive load reduce the power factor . they does not allow sudden change in current in the load ...
Current stops going into a capacitor when it's voltage is equal to the supply voltage. From then there is no flow of current, so there is no magnetic field. Yet the capacitor remains charged and has energy to release if required.
If by power supply you mean a voltage source, it really won't matter that the resistor is removed. The voltage source will provide infinite current, instantly charging the capacitor so that the capacitor's voltage is equal to the source.Alternative AnswerIf you are referring to an a.c. circuit, then a load current will continue to flow with its value being determined by the capacitive reactance of the circuit, and the resulting phase angle will lead the supply voltage be very close to 90 degrees.
A: The leakage is an additional load to the bridge effect is that the capacitor will get hot then hotter because of it leaks more eventually blows hopefully open or dead short. both of these scenario may save the power supply.
inverse of frequencyAnswerReactance is inversely-proportional to frequency of the supply, and the capacitance of the capacitor.
It depends on how the capacitor is connected and whether the supply voltage is a.c. or d.c. Assuming you are talking about a power-factor improvement capacitor (connected in parallel with an inductive load, supplied with a.c.), then the supply current will reduce.
A capacitor and a resistor has no effect on the supply voltage; however, this particular load combination will cause the load current to lead the supply voltage by some angle termed the 'phase angle'.
It depends on how the capacitor is connected and whether the supply voltage is a.c. or d.c. Assuming you are talking about a power-factor improvement capacitor (connected in parallel with an inductive load, supplied with a.c.), then the supply current will reduce.
Electrical current alone has no heating effect. Current through a device, with a voltage across the device will have a heating effect. The equation for calculating it is power = voltage x current, where power is proportional to the heating effect If the AC supply is measured as an RMS voltage and an RMS current and the device is resistive, then the heating effect will be identical to the same values with a DC supply. RMS means the "average" voltage or current of an AC supply whereas the peak AC voltage refers to the highest voltage that is reached on each cycle. However, if the device is not just resistive but is inductive, the heating effect will be lower with an AC supply than with a DC supply. By inductive, we mean that the device has a coil or capacitor, for example, in the circuit. The reasons why are outside the scope of this answer but are explained in many electronics text books, or look up "power factor" on google
You would use a supply bypass capacitor in a common collector amplifier... It's necessary, to give the positive supply rail a direct AC connection to ground. Without it, I don't think the amplifier would work properly. However, if you're using a power supply and not a battery, then chances are that it HAS a big capacitor inside it, eliminating the need for any external capacitor.
is it ? are you sure ? but i know so many circuit where capacitor is connected with ac supply . still , if u connected a capacitor to dc supply , then : 1. if it is in SERIES with the dc supply , it will block all the dc current as capacitor provides infinite resistance to dc current . application : where u want to block dc current.(simple high pass filter) 2. if it is in PARALLEL with the dc supply , it will not block dc current , but if any ac current comes out from the supply , the ac current will go through the capacitor , as capacitor provides small resistance to ac current. application : a) where u want to block ac current.(simple low pass filter) b) to filter the noise (ac components) of dc supply.
inductive load does not allow the current to become zero eve though the supply source get removed . inductive load reduce the power factor . they does not allow sudden change in current in the load ...
The load current will lag the supply voltage by an angle called a 'phase angle', determined by the values of resistance and inductive reactance. The magnitude of the load current will be determined by the impedance of the circuit, which is the vector sum of the resistance and inductive reactance.
capacitor acts as a small battery ,during rectification ac to dc it gets some blank space (no current) to fill this current from capacitor is used.
The active power of an inductor is zero. As we know, the active power is the result of product of supply voltage and in-phase component of load current. But the load current in pure inductive load lags supply voltage by 90 degrees. So there is no component of load current that is in-phase with the supply voltage. Therefore, the active power in inductive reactance is zero.
when the current supply to the capcitor it can store or hold little amount of charge
inductive load does not allow the current to become zero eve though the supply source get removed . inductive load reduce the power factor . they does not allow sudden change in current in the load ...