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Normally the acceleration of gravity is not a factor in the period of a simple pendulum because it does not change on Earth, but if it were to be put on another celestial body the period would change. As gravity increases the period is shorter and as the gravity is less the period is longer.
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
You can use a simple pendulum, measure how long one period takes, then use the formula for a pendulum, and solve for gravitational acceleration.
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
The time period of a simple pendulum is calculated using the following conditions: Length of the pendulum: The longer the length of the pendulum, the longer it takes for one complete back-and-forth swing. Acceleration due to gravity: The time period is inversely proportional to the square root of the acceleration due to gravity. Higher gravity results in a shorter time period. Angle of displacement: The time period is slightly affected by the initial angle of displacement, but this effect becomes negligible for small angles.
The simple pendulum can be used to determine the acceleration due to gravity.
T=2pi(l/g)1/2
Normally the acceleration of gravity is not a factor in the period of a simple pendulum because it does not change on Earth, but if it were to be put on another celestial body the period would change. As gravity increases the period is shorter and as the gravity is less the period is longer.
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
You can use a simple pendulum, measure how long one period takes, then use the formula for a pendulum, and solve for gravitational acceleration.
known to be seconds pendulum,the length would be almost 1m when acceleration due to gravity is 9.8m/s2
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
The time period of a simple pendulum is calculated using the following conditions: Length of the pendulum: The longer the length of the pendulum, the longer it takes for one complete back-and-forth swing. Acceleration due to gravity: The time period is inversely proportional to the square root of the acceleration due to gravity. Higher gravity results in a shorter time period. Angle of displacement: The time period is slightly affected by the initial angle of displacement, but this effect becomes negligible for small angles.
physical meaning of experiment of acceleration of free fallby means of the simple pendulum
i think it is infinite because acceleration due to gravity at the center of the earth is zero and time period of the simple pendulum is given by 2*3.14*sqrt(l/g)....
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).