increasing the concentration increases the rate of the reaction
The formula is:r = k(T) · [A]n'· [B]m' where:- r is the rate of reaction- k is the rate constant- [A] and [B] are the concentrations of the reactants- n' and m' are the reaction orders- T is the temperature
the experimental rate law of a simple reaction A->B+C is v=k[A].calculate the change in the reaction rate when:(a) the concentration of A is tripled (b) the concen-tration of A is halved
In general (but not always), the reaction rate will increase with increasing concentrations. If the reaction is zero order with respect to that substance, then the rate will not change.
Usually, increasing concentration of reactants increases the rate of reaction, but increasing concentrations of products reduces the rate of reaction. However, if one reactant is already present in large stoichiometric excess over another, increasing the concentration of that reactant may not increase the rate of reaction at all, and if the free energy of reaction is large enough in magnitude, increasing the concentration of products may not reduce the rate of reaction at all.
rate laws a+the higher the concentration = more particles = higher chance of a collision happening = higher/faster reaction rate
The rate of reaction is dependent on the concentration of the various reactants whereby, the more the concentration, the higher the reaction rate.
The effect of concentration of reactants on rate of reaction depends on the ORDER of the reaction. For many reactions, as the concentration of reactants increases, the rate of reaction increases. There are exceptions however, for example a zero order reaction where the rate of reaction does not change with a change in the concentration of a reactant.
The effect of concentration of reactants on rate of reaction depends on the ORDER of the reaction. For many reactions, as the concentration of reactants increases, the rate of reaction increases. There are exceptions however, for example a zero order reaction where the rate of reaction does not change with a change in the concentration of a reactant.
The concentration of reactants is changed.
The formula is:r = k(T) · [A]n'· [B]m' where:- r is the rate of reaction- k is the rate constant- [A] and [B] are the concentrations of the reactants- n' and m' are the reaction orders- T is the temperature
increasing the concentration increases the rate of the reaction
Increasing the concentration increases the molecules' collision frequency.
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
For a reversible reaction, the concentration of the products will be more as it approaches the equilibrium. So the rate of reverse reaction will increase and the rate of forward reaction will slow down.
the experimental rate law of a simple reaction A->B+C is v=k[A].calculate the change in the reaction rate when:(a) the concentration of A is tripled (b) the concen-tration of A is halved