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The mass is protons + neutrons. So, if the mass is 9 and it has 5 neutrons, then there must be FOUR (4) protons. This would be the element beryllium (Be).
It boron element. Atomic mass of it is 10.8.
That would Beryllium, with an atomic number of 4 and mass number of 9Hope this helped!
4 protons 4 electrons 5 neutrons subtract the number of of protons from the atomic weight
Boron: Boron's mass number is 10.811 rounded to 11.11 - 5 (Z or element number) = 6
Boron: Mass is 10.811 11 - 5 (Z or element number) = 6 neutrons.
The mass is protons + neutrons. So, if the mass is 9 and it has 5 neutrons, then there must be FOUR (4) protons. This would be the element beryllium (Be).
It boron element. Atomic mass of it is 10.8.
That would Beryllium, with an atomic number of 4 and mass number of 9Hope this helped!
4 protons 4 electrons 5 neutrons subtract the number of of protons from the atomic weight
Boron: Boron's mass number is 10.811 rounded to 11.11 - 5 (Z or element number) = 6
Atomic Mass Number Of Boron.The Atomic Mass Number Of Boron Is 10.81 Its Atomic number is 5. It has 5 p neutrons , 6 neutrons and 5 electrons. Its valency is 3. it has 3 valence electrons.
The number of protons in an element is its atomic number. Boron's atomic number is 5 - ergo, there are 5 protons. The number of neutrons in an element is the difference between the atomic mass and the atomic number of an element. boron's atomic mass is 11. Therefore, 11 - 5 = 6. There are 6 neutrons in boron. In conclusion, there are 6 neutrons and 5 protons in boron.
To the find the mass number of an atom you add the protons and neutrons. Meaning that the mass number of this atom is 12.
The mass number 5 is not compatible with the number of neutrons 10.
Disregard the electrons, as their relative mass is insignificant to that of protons and neutrons. To find atomic mass, add the numbers of protons and neutrons: 5 + 6 = 11 is the mass number.
5: The mass number of an isotope is always the sum of the numbers of protons and neutrons in a nucleus of elements of the isotope.