The element Ar 4s2 3d10 4p6 is Krypton (Kr).
what is the element with a noble gas configuration of [ar] 4s2 3d10 4p4
what peroid is this element in
Sc
(The question is partially mis-typed)
Potassium's shortnote electron configuration is [19K] = [20Ar] 4s1 (not 5s1)
The element ending with ..., 5s1 only rubidium (37Rb) is possible: [36Kr] 5s1 (not Ar)
Argon electron configuration is [Ar] = 1s2, 2s2 2p6, 3s2 3p6, (4s0) and
Krypton electron configuration is [Kr] = 1s2, 2s2 2p6, 3s2 3p6, 4s2 4p6 4d10, (5s0)
Ca
cr
B
Selenium Se
Krypton
cr
Neutral calcium has 20 protons and 20 electrons. The first 20 atomic orbitals are filled as 1s2 2s2 2p6 3s2 3p6 4s2. The shorthand for this is [Ar] 4s2 since argon's configuration is 1s2 2s2 2p6 3s2 3p6.
[Ar] 3d2 4s2
Scandium forms compounds with the Sc3+ ion, losing both the 4s2 and 3d1 electrons. With no electrons in the d orbitalks its sakts are colorless.
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5 or [Ar] 4s2 3d10 4p5
1s 2 2s 2 2p6 3s2 3p6 4s2 or Ar 4s2 (Noble gas form) In noble gas form, you go back to the noble gas (the last group on the Periodic Table) prior to the element you are writing the configuration for. The electron configuration is the same up until that point. Then you write down the difference. In this example, the electron configuration for Argon (Ar) is 1s2 2s2 2p6 3s2 3p6. If you fill up the shells until 4s2, you get calcium. It's faster to abbreviate by saying "Ar 4s2"
The electronic configuration of Scandium (Sc) is [Ar] 3d1 4s2.
The noble gas notation of scandium is [Ar] 3d1 4s2, where [Ar] represents the electron configuration of the noble gas argon. Scandium has 21 electrons, with the electron configuration of [Ar] 3d1 4s2.
Noble gas notation for scandium (Sc) is [Ar] 3d1 4s2, where [Ar] represents the electron configuration of argon (1s2 2s2 2p6 3s2 3p6).
It is [Ar] 3d1 4s2
The short form is [Ar] 3d1 4s2
The noble gas electron configuration of scandium is [Ar] 4s2 3d1. Scandium has 21 electrons, and the noble gas configuration represents the nearest noble gas to scandium, which is argon with 18 electrons.
Ca
The element with 27 protons is cobalt and its electron configuration is [Ar] 3d7 4s2.
The element scandium (atomic number 21) has the electron configuration [Ar] 3d1 4s2 Actually the correct configuration is [Ar] 4s2 3d1 this is because d comes after s in the ladder The ladder goes as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p
Transition metal and is a d-block element. :) ~Scandium~
Bromine atom
The correct electron configuration for Calcium (Ca) is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2.