http://upload.wikimedia.org/math/6/e/3/6e306f943fc864e7ee41a1b3a7f16172.png
Where:
Vt = terminal velocity m = mass of the falling object g = acceleration due to gravity (~9.88ms-2) Cd = drag coefficient (see http://en.wikipedia.org/wiki/Drag_coefficient) ρ = density of the fluid through which the object is falling A = projected area of the object Taken from Wikipedia.
The equation to determine an object's terminal velocity is v_terminal = √(2 * m * g / ρ * A * C_d), where v_terminal is the terminal velocity, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, A is the cross-sectional area of the object, and C_d is the drag coefficient.
Take an accelerometer with you when you jump, and at the point that it reads, "zero", the terminal velocity has been reached.
v=f/lambda
down and up forces balance at terminal velocitymass * g = v^2 * drag coefficientif mass and terminal velocity are known , drag coefficient can be foundsay mass = 100 kg, g = 9.8 (m/s)/s, terminal velocity = 70 m/sso at terminal velocity:100*9.8=4900* drag coefficientthen:100*9.8/4900 = 0.2 (drag coefficient)if you reduce the drag coefficient, the terminal velocity will increase, until the forces balance
In that case, the object is said to have achieved terminal speed.
Passing the terminal velocity is clearly not possible, otherwise it could not be called the terminal velocity!
The surface area is the variable to determine how fast an object will be moving when it reaches terminal velocity.
Take an accelerometer with you when you jump, and at the point that it reads, "zero", the terminal velocity has been reached.
v=f/lambda
determine the equation for trajectory with ahead of 7.0m and velocity cofficient of .95
There is no such thing as "maximum terminal velocity", neither on Jupiter nor hear on Earth. The "terminal velocity" depends on the specific object - and on the atmospheric conditions. For example, a very heavy object will typically have a larger terminal velocity than one that is very light; and near Earth's surface, the terminal velocity (for a given object) will be smaller than in the upper atmosphere, where there is less air resistance.
Momentum= Mass X Velocity
It depends on the height of the tower and the terminal velocity of the specific rubber ball. Many objects with a specific gravity near 1 have a terminal velocity of about 120 miles per hour.
If air resistance is significant, after falling for a while the air resistance will be as strong as the force of gravity; the two forces will be in equilibrium, and the object won't accelerate any more. This velocity is called "terminal velocity". The amount of this terminal velocity, and the time it takes to approach the terminal velocity, depends on the specific object that is falling.
A parachute increases drag, slowing the fall of an object and reducing its terminal velocity. As the parachute deploys, it captures air and creates resistance, causing the object to fall more slowly towards the ground.
down and up forces balance at terminal velocitymass * g = v^2 * drag coefficientif mass and terminal velocity are known , drag coefficient can be foundsay mass = 100 kg, g = 9.8 (m/s)/s, terminal velocity = 70 m/sso at terminal velocity:100*9.8=4900* drag coefficientthen:100*9.8/4900 = 0.2 (drag coefficient)if you reduce the drag coefficient, the terminal velocity will increase, until the forces balance
In that case, the object is said to have achieved terminal speed.
Passing the terminal velocity is clearly not possible, otherwise it could not be called the terminal velocity!