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What form of the idea gas law would you use to calculate the number of moles?
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What form of the ideal law would you use to calculate the number of moles of a gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of ideal gas law would you use to calculate the number of moles of a gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of the ideal gas law would you use to calculate the number of moles of the gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of the ideal gas law would use to calculate the number of moles of a gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of the ideal gas law would you use to calculate the number of the moles of a gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of the ideal gas law would you use to calculate the number of moles of gas?
From PV = nRT you solve for n (moles). Thus, n = PV/RT
What form of the ideal gas law would you use to calculate temperature of a gas?
The formula is: T = PV/nR, Where: * T is the temperature in kelvin * P is the pressure in atmospheres * n is the number of moles * R is the gas constant
What form of the ideal gas law would you use to calculate the temperature of a gas?
The formula is: T = PV/nR, Where: * T is the temperature in kelvin * P is the pressure in atmospheres * n is the number of moles * R is the gas constant
What form of ideal gas law would you use to calculate the temperature of a gas?
The formula is: T = PV/nR, Where: * T is the temperature in kelvin * P is the pressure in atmospheres * n is the number of moles * R is the gas constant
The relative number of moles of hydrogen to moles of oxygen that react to form water represent what?
Mole Ratio
How many moles of NaCl would form from 3.25 moles of NaHCO3?
The same amount.
How many grams of solid sodium hydroxide would need to be added to completely neutralize 35.0 mL of 1.45 M HBr?
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
