AgCl and KNO3.
The balanced equation is as follows: KIO3 + AgNO3 --> KNO3 + AgIO3
AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq) This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
AgNO3(aq) + HCl(aq) --> AgCl(s) + HNO3(aq)
equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]
The names would be silver chloride and potassium nitrite. The formula would be AgNO3(aq) + KCl(aq) = AgCl (s) + KNO3 (aq).
It forms AgCl + KNO3 or Silver chloride + potassium nitrate
Potassium chloride is react with AgNO3 , the chloride ion subtract from potassium chloride to form silver chloride precipitate and potassium nirate. KCl + AgNO3 → KNO3 + AgCl↓
The balanced equation is as follows: KIO3 + AgNO3 --> KNO3 + AgIO3
AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq) This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
AgNO3(aq) + HCl(aq) --> AgCl(s) + HNO3(aq)
the reaction is as follows-AgNO3 + KCl ----->AgCl +KNO3here the silver nitrate(AgNO3) reacts with potassium chloride(KCl) to form potassium nitrate(KNO3) and insoluble AgCl.
yes
equivalent weight of silver nitrate = 169.87 so 0.1 N Ag NO3 = 16.987 gm /litre of AgNO3 now equivalent weight of KCl = 74.55 so 0.1 N KCl = 7.455 gm/litre so 0.1 N AgNO3 = 0.1N KCl = 7.456 gm of KCl [ not mg ]
alcl3+hno3
It is a "double replacement" reaction between silver nitrate and potassium chloride, to yield silver chloride and potassium nitrate.AgNO3+ KCl → AgCl + KNO3
Kcl means potasiam chloride and cl means chlorin . kcl is a compound and cl is an element . when cl react with k a compound produce called kcl.
These compounds react forming a white insoluble precipitate - silver chloride: NaCl + AgNO3 = AgCl + NaNO3