AgNO3(aq) + KCl(aq) = AgCl(s) + KNO3(aq)
This is the classic taste for halogens. In thisd case AgCl precipiates down as a white solid.
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The reaction of the above ionic equation will be a very complicated formula. This seems very complicated to the average person but it means a lot to scientists who study ionic reactions. Unfortunately when I try to list the formula for the resulting equation I get an error.
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
CH3COOH + AgNO3
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The chemical equation is:3 AgNO3 + FeCl3 = 3 AgCl + Fe(NO3)33 Ag + 3 NO3- + Fe3+ + 3 Cl- = 3 AgCl(s) + 3 NO3- + Fe3+
The reaction of the above ionic equation will be a very complicated formula. This seems very complicated to the average person but it means a lot to scientists who study ionic reactions. Unfortunately when I try to list the formula for the resulting equation I get an error.
3 AgNO3 + Na3 PO4-->Ag3 PO4 + 3 NaNO3 You need three silver nitrate molecules:one sodium phosphat molecule to complete the reaction. Just swap the ions.
CuCl2(aq) + 2AgNO3(aq) = Cu(NO3)2(aq) + 2AgCl(s)
Agno3+Nacl-
CH3COOH + AgNO3
the equation is, NaBr + AgNO3 = AgBr(pale yellow ppts) + NaNO3(aq.)
AgNO3+NaBr--->NaNO3+AgBr
This equation is: AgNO3 + HCl--------- AgCl + HNO3 AgCl is a white precipitate.
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This reaction can occur according to the equation Cu + AgNO3 = CuNO3 + Ag or according to the equation Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag, depending on whether Cu(I) or Cu(II) nitrate is formed.