ehmm... I'm not sure... what do you want to throw?
If an object falls twice as far, it acquires twice as much potential energy due to the increase in height. The increase in potential energy is directly proportional to the distance the object falls.
for how fast an object falls, use v=gt. g stands for the acceleration of gravity- 9.8 m/s2 v stands for speed t stands for time for how far that object falls, use d=0.5gt2 d being distance
That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.
To calculate how far an object has moved, you can multiply the object's speed by the time it has been moving. Distance = Speed x Time. This formula will give you the distance traveled by the object during that time period.
The formula to determine distance based on echo time is: Distance = (echo time * Speed of sound in air) / 2. Since sound travels at approximately 343 meters per second in air, if the echo takes 9 seconds to return, the distance from the object would be approximately 1543.5 meters away.
Ignoring air resistance, it would be 706 meters .
The answer is 91 ft, of course!
Distance traveled can be calculated using the formula: distance = speed × time. This equation is used to determine how far an object has moved over a certain period of time at a specific speed.
When an object falls, it reaches terminal velocity due to air resistance. Terminal velocity is the constant speed an object will reach when the force of gravity pulling it down is equal to the force of air resistance pushing against it. At terminal velocity, the object stops accelerating and falls at a constant speed.
Okay so I am not good at this, but I think it is d = (1/2)g*t^2.
The equation for the distance fallen by an object freely falling from rest can be calculated using the formula d = (1/2) * g * t^2, where d is the distance fallen, g is the acceleration due to gravity (approx. 9.81 m/s^2), and t is the time elapsed.
Every second, it falls farther and faster than it fell in the previous second.