Okay so I am not good at this, but I think it is d = (1/2)g*t^2.
The equation for the distance fallen by an object freely falling from rest can be calculated using the formula d = (1/2) * g * t^2, where d is the distance fallen, g is the acceleration due to gravity (approx. 9.81 m/s^2), and t is the time elapsed.
The "d" in the free fall equation corresponds to the displacement or distance the object falls vertically under the influence of gravity. It represents how far the object has fallen from its initial position.
If an object falls twice as far, it acquires twice as much potential energy due to the increase in height. The increase in potential energy is directly proportional to the distance the object falls.
for how fast an object falls, use v=gt. g stands for the acceleration of gravity- 9.8 m/s2 v stands for speed t stands for time for how far that object falls, use d=0.5gt2 d being distance
That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.That would be the escape velocity of Earth, about 11.2 km/sec. I am assuming that the object falls from far, far away, and that air resistance is negligible.
ehmm... I'm not sure... what do you want to throw?
Ignoring air resistance, it would be 706 meters .
The answer is 91 ft, of course!
Assuming the object starts from rest, the distance an object falls in 0.25 seconds can be calculated using the equation ( d = \frac{1}{2}gt^2 ), where (d) is the distance, (g) is the acceleration due to gravity (9.8 m/s²), and (t) is the time. Substituting the values, the object would fall approximately 0.31 meters in 0.25 seconds.
When an object falls, it reaches terminal velocity due to air resistance. Terminal velocity is the constant speed an object will reach when the force of gravity pulling it down is equal to the force of air resistance pushing against it. At terminal velocity, the object stops accelerating and falls at a constant speed.
The distance an object moves depends on factors such as the force applied, the time over which the force is applied, and the object's mass. The distance traveled can be calculated using the equation distance = rate x time.
Every second, it falls farther and faster than it fell in the previous second.