This formula is for citrate ion; the mass is 191,1 g.
The molecular weight of Sodium citrate is approximately 258.07 grams per mole.
The molecular weight of citrate is approximately 192.13 g/mol.
sodium citrate (Na3C6H5O7) molar mass=258.069g/mol
sodium citrate (Na3C6H5O7) molar mass=258.069g/mol
gram molecular weight of C6H8O7=(atomic weigth of carbon X 6)+(atomic weigth of hydrogen X 8+(atomic weigth of oxygen X 7) grams
To calculate the empirical formula from a molecular formula, divide the subscripts in the molecular formula by the greatest common factor to get the simplest ratio of atoms. This simplest ratio represents the empirical formula.
molecular structur C9H8K2O4molecular weight: 258.35
To find the molecular formula, you first need to calculate the empirical formula mass of C3H4. C3H4 has an empirical formula weight of 40 g/mol. If the molecular weight is 120 g/mol, then the molecular formula would be 3 times the empirical formula, so the molecular formula would be C9H12.
Iron(II) sulphate Chemical formula is FeSO4 The molecular weight is 151,908 g (for the anhydrous salt)
To calculate the gram molecular weight of an unknown liquid, you need to determine the molecular formula of the liquid and then add up the atomic weights of all the atoms in the formula. This will give you the gram molecular weight of the unknown liquid.
Technically... not really. It would perhaps be more accurate to use the terms formula mass and molecular mass rather than formula weight and molecular weight. This because in physical terms, weight is a force while mass is a measure of the amount of substance in something.
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.