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The fulcrum should be as far as possible from the effort to minimise the force needed. It should also be as close to the load as possible.
This will occur if the fulcrum is closer to the load than the effort.
confusing
chickjenww
inclined plane
The fulcrum should be as far as possible from the effort to minimise the force needed. It should also be as close to the load as possible.
The magnitude of the effort is controlled by you, not by the distance of the load from the fulcrum. Moving the load farther away from the fulcrum has no effect on the effort. But if you want to leave the effort where it is and still lift the load with the lever, then you're going to have to increase the effort.
A relationship between two of it are when load come closer to fulcrum, you need more effort to use. But if load go far away from the fulcrum, you need less effort to use. A relationship between two of it are when load come closer to fulcrum, you need more effort to use. But if load go far away from the fulcrum, you need less effort to use.
This will occur if the fulcrum is closer to the load than the effort.
No, the function of the fulcrum remains the same The only change would be the ratio of force to load The closer the fulcrum is the the load, the less force required to lift it The farther away the fulcrum is from the load, the more force required to lift it
confusing
The fulcrum is between the effort and the load.
The fulcrum is the swing hinges and the effort is the seat, you sitting in it would be the load.
To do this you first have to calculate your ideal mechanical advantage (IMA). The IMA is equal to the effort distance (the distance from the fulcrum to where you will apply the effort) divided by the load distance (the distance from the fulcrum to the load). You can then set your IMA equal to your acutal mechanical advatage (AMA) which assumes 100% efficiency. The AMA is equal to the load force (the weight of what you are lifting) divided by the effort force (the # you are looking for). So, for example, if your IMA is 5 and your load force is 500 lbs: 5=500/effort force. Therefore the effort force would be 100 pounds.
chickjenww
inclined plane
the position is that lever is near fulcrum exposed to the left sex of the effort which makes the effort to troposphere