The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst
2H2O2(l)-------------> 2H2O(l) + O2(g)
KI+MnO2+H2SO4=KI+MnSO4+KHSO4+H2O
approx 2.4354g
ki is added to liberate iodine gas . this liberated iodine gas was then titrated with sodium thiosulphate to give a permanent white precipitate. this white precipitate indicates the endpoint of the titration..
Yes, AgI is insoluble, therefore will form a precipitate.
Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3
H2O2 + 2 KI --> 2 KOH + I2
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
The mechanism of catalysis involves the I- ion only. The mechanism is: H2O2 + I- --> IO- + H2O H2O2 + IO- --> I- H2O O2 Second step regenerates the I- ion (thus acts as a catalyst). This reaction is first order wrt to both H2O2 and I-. Notably exothermic reaction. Must be in a medium which allows formation of I-, ie dissociation of KI. Water is a wonderful example.
KI+MnO2+H2SO4=KI+MnSO4+KHSO4+H2O
approx 2.4354g
Literally, the correct formula for potassium and iodine at standard temperature and pressure would be " K and I2". The formula for the compound formed between potassium and iodine, however, is KI.
KI or potassium iodide. See the related link for more information.
ban ki moon
ki is added to liberate iodine gas . this liberated iodine gas was then titrated with sodium thiosulphate to give a permanent white precipitate. this white precipitate indicates the endpoint of the titration..
Nothing, Naphthalene is an organic compound and can not mixed with ionic compound KI.
Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3
Yes, AgI is insoluble, therefore will form a precipitate.