it would be called a step up transformer
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
It depends on how much voltage you have applied. If you apply rated voltage nothing happens only core losses will be there on the transformer nothing will happen apart from that. If you go on increase the voltage core losses will increase and transformer will get heated up. After attaining the breakdown voltage of insulation, insulation in the primary and secondary will fail and the coils will get short circuited then the coils will burn.
If the number of turns in the primary is the same as the secondary, this would be an isolation transformer. Primary and secondary voltages should match (minus the inherent transformer losses), as should the current.
there will be no neutral point in the circuit and high voltage will be across the transformer coils
The secondary of a CT must always have a load connected. An open circuit secondary can result in the development of a dangerously high secondary voltage. If a CT is energized but is not used, the output terminals of the CT must be shorted out.
Frequency does not change when you use a step-up or step-down transformer. Only current and voltage is changed.
If there is a short circuit between the transformer's high-voltage windings and its core (or any other metal parts, come to that) the fault will be recognised by the high-voltage supply's protective system, which will quickly disconnect the high-voltage line. For this to happen, the metal parts of the transformer, including its core and metal container, must be earthed or grounded to provide an electrical path back to the source of the high voltage.
the winding would burn....
If rated voltage is applied to Transformer during S/C test, The secondary winding will burn out due ta heavy current flow through the winding. During S/C test the secondary winding is short circuited so the impedance between phase and neutral is very low(only winding resistance). But the voltage across the secondary winding is rated hence heavy current flows through the winding, as I=V/Z. it depends which rated voltage is applied. if you are talking about primary winding voltage, transformer should withstand the primary rated voltage it's been designed for (OR it has been poorly designed). Otherwise, if rated voltage is the insulation voltage between a winding and earth OR winding-to-winding, you just have to check if: 1 - it is higher than the maximum primary winding voltage the transformer can withstand (could be, could not be..). Then, you can guess if your transformer is likely to burn or not. 2 - your test setup (usually a HV generator connected between primary and secondary winding) can deliver the requested current for the setup. I guess this won't be the case, since HV testers are usually designed to generate high voltages, but very small output currents.
If the transformer was designed for the specific frequency in use, it will step up or down voltage and current as it was designed to do. Transformers transform how power "looks" by increasing and decreasing voltage and current, while keeping power output equivalent to input (if you ignore the transformer losses).
we cant give dc supply to a transformer because it will have some constant frequency to work..Dc is not having any frequency component.Comment:Nothing will happen. Transformer works on the principal of electromagnetic induction were an alternating magnetic flux of the primary winding links up with secondary winding via the core. An emf will then be induced in the secondary winding if it's cut by the alternating flux. Only AC can attain this. DC does change directions and hence it won't effect anything.AnswerIf the value of d.c. voltage is equivalent to the transformer's rated primary voltage, then it's very likely that the primary winding will burn out as it has a very low resistance and the resulting current would be high.
If DC voltage is applied to the primary of a transformer the flux produced in the transformer core will not vary but remain constant in magnitude therefore no emf will be induced in the secondary winding except at the time of switching on.Also there will be no self induced emf in the primary winding to oppose the applied voltage and since the resistance of the primary winding is quite low heavy current will flow through it which may result in burning out of primary winding.