it increases
If Rotor resistance is increased torque is increased
ERMM THE RESISTANCE INCREASES ) when longer
L1-L0=(RESISTANCE*AREA)/RESISTIVITY where L1=INIIAL LENGTH and L2=FINAL LENGTH
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
If Rotor resistance is increased torque is increased
when the lengh of the conductor is increased by 25%. find the increase in its resistance
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
when length is increased insulation resistance of cable is decresed i.e.,R is inversely proportional to L where R is resistance L is length
ERMM THE RESISTANCE INCREASES ) when longer
Your question seems to have an idea in it backwards.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
The current at every point in the series circuit becomes slightly less, because the increased length of wire adds slightly more resistance to the loop.
L1-L0=(RESISTANCE*AREA)/RESISTIVITY where L1=INIIAL LENGTH and L2=FINAL LENGTH
If half of its length is increased by 2%, then its entire length is increased by 1%.In order to know how this affects the wire's resistance, we'd want to be able toassume that its composition and cross-section are constant along its length. Thiscould be a risky assumption, especially since the length was increased ... possiblyby stretching the wire, which would certainly affect the cross section.But without overthinking the situation and making myself nervous about it, lets justassume uniform composition and cross-section along the entire length, throughoutthe observation period. Then its resistance also increases by 1%.
If the length of the wire increases its diameter decreases
Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L Now we have R = K * L / pi r^2 Multiplying numerator and denominator by L we get R = K/V * L^2 So resistance is found to be proportional to square of length Hence as length gets increased by 2 times, its resistance value would increase by 4 times.