I assume you mean "What happens if the weight of an object is greater than the weight of the water it displaces." If so, the answer is simple, it sinks. If an objects weighs less than the weight of the water it displaces, it floats.
it floats
Yes, when the object is submerged in water then water exerts opposite buoyonci force which decrease the weight of object.
The water around floating object's is a measure of that object's "Displacement". For the object to float the weight of displacement must equal the object's weight. If the water around an object is of a greater weight than an object's displacement, then the object will sink.
The difference between an object's weight, and the weight of water with the same volume as the object.
Archimedes principle states that : The force of buoyancy is equal to the weight of the displaced water. If the weight of the water displaced is less than the weight of the object , the object will sink. Otherwise the object will float , with the weight of the water displace equal to the weight of the object.
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
The force of Buoyancy in water subtracts from the weight of the object in air.
An object will sink if it has a greater density than water. In this case, the weight of the water displaced by the object is less than the weight of the object.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
the weight of the displaced water is equal to the weight of the object