When red light shines on a red object, the object will reflect the red light and appear red. If white light shines on a red object, the object will absorb all colors except red, which it will reflect, making it appear red as well.
The yellow object will appear dark because it reflects yellow light, which is a combination of red and green light. Since only red light is being shone on it, the object will not reflect any light and will appear black.
The red light would be absorbed by the green object and the object would appear dark. The green object reflects green light and absorbs other colors.
Because white light is made up of all the colors of the spectrum, and an object that appears red in color is simply reflecting the color red, a white object refects all the colors of the spectrum while black objects reflect no colors at all.
Any object that has light shone on it would appear in a particular color because the said object absorbs all the other colors of the spectrum and reflects one single color. when the light itself consists of a single color, the color of the object gets modified because the reflected light contains the color of the light and then part that is reflected. For ex, the wall in the question would appear red if the light is only one wavelength but would appear as a combination of red and its own natural color if the light is a combination of different wavelengths.
The green object will appear black because it will not reflect any of the blue light shone on it. Green objects primarily absorb blue light, so without any green or red light present, the object will appear dark.
I don't know
The yellow object will appear dark because it reflects yellow light, which is a combination of red and green light. Since only red light is being shone on it, the object will not reflect any light and will appear black.
red
BLACK
The red light would be absorbed by the green object and the object would appear dark. The green object reflects green light and absorbs other colors.
it would appear black.
Because white light is made up of all the colors of the spectrum, and an object that appears red in color is simply reflecting the color red, a white object refects all the colors of the spectrum while black objects reflect no colors at all.
Any object that has light shone on it would appear in a particular color because the said object absorbs all the other colors of the spectrum and reflects one single color. when the light itself consists of a single color, the color of the object gets modified because the reflected light contains the color of the light and then part that is reflected. For ex, the wall in the question would appear red if the light is only one wavelength but would appear as a combination of red and its own natural color if the light is a combination of different wavelengths.
On stage in a theatre red light shines and clothes appear red, blue light is shone an clothes appear blue, what colour are they?
The green object will appear black because it will not reflect any of the blue light shone on it. Green objects primarily absorb blue light, so without any green or red light present, the object will appear dark.
Red and blue are primary colours therefore they do not contain any other colour. When a blue light is shone onto a red object, all the blue light is absorbed by the red object, and as no red light is being shone for the red object to reflect, no light will be reflected from it and it will appear to be black. It is important to remember that physical colours will only reflect it's light colour equivalent. All other colours are absorbed. So red will reflect red, green will reflect green, and red will absorb green and so on.
It will appear somewhat Orange. This is due to the roughly 650nM wavelength from the red light and the reflection of the yellow at around 380nM.