Because white light is made up of all the colors of the spectrum, and an object that appears red in color is simply reflecting the color red, a white object refects all the colors of the spectrum while black objects reflect no colors at all.
When lights of any two primary colors are shone on a white object, the object will appear to be a secondary color that is created by mixing those two primary colors together. For example, red and blue light will make the object appear purple, red and green light will appear yellow, and blue and green light will appear cyan.
When red light shines on a red object, the object will reflect the red light and appear red. If white light shines on a red object, the object will absorb all colors except red, which it will reflect, making it appear red as well.
The object will appear white. When an object reflects all colors of light equally, it will appear white because white light is a combination of all colors in the visible spectrum.
Red. The colour of an object is determined by the wavelengths of light it reflects and absorbs, and a white object is one that reflects light across the visible spectrum. If only red light shines on it, it will reflect that light. In contrast, a black object appears black because it doesn't reflect any visible wavelengths, so would still appear black. Any object that doesn't reflect the wavelength of light you're using (eg blue objects) would also appear black because it isn't reflecting any light.
The object will appear white because it reflects all colors of light equally, resulting in a white appearance.
When lights of any two primary colors are shone on a white object, the object will appear to be a secondary color that is created by mixing those two primary colors together. For example, red and blue light will make the object appear purple, red and green light will appear yellow, and blue and green light will appear cyan.
When red light shines on a red object, the object will reflect the red light and appear red. If white light shines on a red object, the object will absorb all colors except red, which it will reflect, making it appear red as well.
blue
red
The object will appear white. When an object reflects all colors of light equally, it will appear white because white light is a combination of all colors in the visible spectrum.
Red. The colour of an object is determined by the wavelengths of light it reflects and absorbs, and a white object is one that reflects light across the visible spectrum. If only red light shines on it, it will reflect that light. In contrast, a black object appears black because it doesn't reflect any visible wavelengths, so would still appear black. Any object that doesn't reflect the wavelength of light you're using (eg blue objects) would also appear black because it isn't reflecting any light.
The object will appear white because it reflects all colors of light equally, resulting in a white appearance.
The white light splits into a spectrum.the original colors will appear. This is referred as REFRACTION.
The object will appear white under white light if it reflects all the colors of light. This is because white light is a combination of all visible colors in the spectrum.
A white object would appear to be red under a red light because the object reflects red light and absorbs other colors. This is because the color of an object depends on the wavelengths of light it reflects.
A white object emits light in all/most of the visible spectrum evenly.Because it reflects all the light back.
When you see color, it is not due to the fact that a specific object is that color, but you are really seeing the light reflected off of the object. A green object reflects only green light, a purple object only reflects purple light. White is a special case, as it reflects all light that hits it. When you shine a white light, the light contains every color that the human eye can see. By using a red filter, you only allow red light to reach the ball. Since the ball reflects all light, it reflects the only light it recieves, red light. Therefore, you percieve the ball as being red.