Assuming the temperature is constant and none of the air is let out of the balloon, if you half the volume, the air pressure will double.
If you want it, here is the math:
Air is approximately an ideal gas, so when the temperature is constant, it follows the gas law of P1*V1 = P2*V2 where P1 is the pressure at state 1 (i.e. before the balloon is squeezed), V1 is the volume at state 1, P2 is the pressure at state 2 (i.e. after the balloon is squeezed), and V2 is the volume at state 2. When you half the volume, mathematically saying V2 = 0.5*V1. When you substitute this in, your equation now becomes P1*V1 = P2*0.5*V1. The V1 on both sides will cancel, leaving you with P1 = 0.5*P2. Since you are asking about the pressure after you squeeze the balloon, you want to know P2. So if you divide both sides by 0.5, you now have P1/0.5 = P2 or equivalently P2 = 2*P1 and we see that the pressure is twice that of the original.
assuming the balloon is closed, the air pressure would double
The force of the pressure put on the balloon is squeezed into smaller particles so the volume is smaller. :) From Jade Nicole White. X
volume decreases considering the pressure is constant
The pressure of the gas would rise. Explain? OK, Blow up a balloon and tie the end. Decrease volume of the container (step on balloon). Balloon explodes (Pressure rose)
Because hot air rises, the warmest air in the balloon is at the top of it. As time passes the balloonist has to fire the burners to maintain the temperature of the air in the balloon, and to prevent it being squeezed put by the higher pressure of the cold air surrounding the balloon.
assuming the balloon is closed, the air pressure would double
The force of the pressure put on the balloon is squeezed into smaller particles so the volume is smaller. :) From Jade Nicole White. X
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
The pressure will increase 3 fold
Isothermal is where pressure and/or volume changes, but temperature remains constant. Pressure, Volume, and Temperature are related as: PV = nRT =NkT for an ideal gas. Here, we see that since a balloon's volume is allowed to change, its pressure remains relatively constant. Whenever there is a pressure change, it'll be offset by an equivalent change in volume, thus temperature is constant.
3.5 litre if pressure is kept constant.
volume decreases considering the pressure is constant
The volume will increase in proportion to the increase in absolute temperature.
The volume will increase in proportion to the increase in absolute temperature.
Same throughout the ballon according to the Pascal's principle
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