As a series circuit, as asked, all bulbs will go off because of that just one bulb.
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
They dim as the total resistance of series of resistances is the sum of the resistances; and current = V/R.
Overall brightness (not individual bulbs' brightness) will increase when we connect them in parallel & it will decrease when we connect them in series.
In a parallel circuit, each bulb receives the full voltage of the power source, so all bulbs shine at their full brightness. In a series circuit, the brightness of each bulb decreases as more bulbs are added because the voltage is shared among all bulbs.
The voltage in a series circuit is divided among the bulbs, so as more bulbs are added in series, each bulb receives less voltage. This causes the brightness of each bulb to decrease compared to when fewer bulbs are present.
at like 1minute after each other.
In a parallel circuit, the brightness of the bulbs connected depends on their resistance and current flow, not their physical shape or size. The bulbs will have the same voltage across them, so if the long bulb has a lower resistance, it could be brighter but this depends on the specific characteristics of the bulbs.
If they have the same resistance they will. Kirchhoff's' Law.
-- If the bulbs are in parallel, then the addition of a bulb has no effect on the brightness of those that were there before. -- If the bulbs are in series, then the addition of a bulb causes the brightness of those that were there before to decrease. (And I wasn't even there when you did the experiment !)
In a parallel circuit, adding more light bulbs does not decrease the brightness of the existing bulbs. Each bulb operates independently and receives the full voltage of the power source, so their brightness remains consistent regardless of how many bulbs are added. However, the total current drawn from the power source will increase with each additional bulb.
If three identical bulbs are connected in parallel to a battery, all three bulbs would have equal brightness.Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that, in a parallel circuit, the voltage across each parallel element is the same.There are effectively 6 series circuits in this example - battery and A - battery and B - battery and C - A and B - A and C - and B and C. These six combinations are also parallel circuits, and they are also in parallel with each other.
The bulb is dim.Because,the voltage is drops in series connection so you add more bulbs in series the last bulb got low voltage that reason for the bulb is dim