When the wavelength (λ) increases, the frequency (v) decreases. When the λ goes down, the v goes up.
The freequency of a wave is increased when the wavelength is decreased. This is because the product of the frequency and the wavelength are a constant that determines the speed of the wave c=fw.
If you are talking about an electromagnetic wave; energy is proportional to frequency (E=hf), and frequency is inversely proportional to wavelength (wavelength equals velocity divided by frequency). So when the wavelength is increased, the energy is decreased.
If the speed is increased and the frequency stays the same, the wavelength will also increase. Wavelength is inversely proportional to speed for a constant frequency, so as the speed increases, the wavelength will also increase.
When the amplitude and frequency of a wave are both increased, the wavelength remains constant. Amplitude affects the intensity or loudness of the wave, while frequency determines the pitch. Therefore, changing the amplitude and frequency does not alter the wavelength of the wave.
When wavelength decreases, frequency increases, and when wavelength increases, frequency decreases. The product of (wavelength) times (frequency) is always the same number ... the speed of the wave. So when one of them changes, the other one must change in the opposite direction in order for their product to remain unchanged.
As the frequency goes up, the wavelength decreases. Their product is always the same number . . . the wave's speed.
If frequency is tripled, the wavelength will be one-third of its original value. This is because the speed of the wave remains constant, so as frequency increases, wavelength decreases to maintain a constant speed.
As wavelength increases the frequency decreases.
If the speed increased and the wavelngth stayed the same then the frequency would have to increase. Because Speed=Frequency*Wavelength Hope that helps
If the frequency is increased the wavelength will be decreased. Wavelength lambda and frequency f are connected by the speed c of the medium. c can be air = 343 m/s at 20 degrees celsius or water at 0 dgrees = 1450 m/s. c can be light waves or electromagnetic waves = 299 792 458 m/s. The formulas are: c = lambda x f f = c / lambda lambda = c / f
Wavelength = 1/frequency. If you double the frequency, the wavelength drops to half.
The wavelength is halved.