When wavelength decreases, frequency increases, and
when wavelength increases, frequency decreases.
The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave. So when one of them changes, the other one must
change in the opposite direction in order for their product to remain unchanged.
In this case, the wavelength increases. The wavelength, multiplied by the frequency, is equal to the speed of the wave - and in most types of waves, the speed is more or less independent of the frequency.
If the speed is increased and the frequency stays the same, the wavelength will also increase. Wavelength is inversely proportional to speed for a constant frequency, so as the speed increases, the wavelength will also increase.
When the amplitude and frequency of a wave are both increased, the wavelength remains constant. Amplitude affects the intensity or loudness of the wave, while frequency determines the pitch. Therefore, changing the amplitude and frequency does not alter the wavelength of the wave.
If the frequency is increased the wavelength will be decreased. Wavelength lambda and frequency f are connected by the speed c of the medium. c can be air = 343 m/s at 20 degrees celsius or water at 0 dgrees = 1450 m/s. c can be light waves or electromagnetic waves = 299 792 458 m/s. The formulas are: c = lambda x f f = c / lambda lambda = c / f
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
If you are talking about an electromagnetic wave; energy is proportional to frequency (E=hf), and frequency is inversely proportional to wavelength (wavelength equals velocity divided by frequency). So when the wavelength is increased, the energy is decreased.
The freequency of a wave is increased when the wavelength is decreased. This is because the product of the frequency and the wavelength are a constant that determines the speed of the wave c=fw.
In this case, the wavelength increases. The wavelength, multiplied by the frequency, is equal to the speed of the wave - and in most types of waves, the speed is more or less independent of the frequency.
When the wavelength (λ) increases, the frequency (v) decreases. When the λ goes down, the v goes up.
If the speed is increased and the frequency stays the same, the wavelength will also increase. Wavelength is inversely proportional to speed for a constant frequency, so as the speed increases, the wavelength will also increase.
When the amplitude and frequency of a wave are both increased, the wavelength remains constant. Amplitude affects the intensity or loudness of the wave, while frequency determines the pitch. Therefore, changing the amplitude and frequency does not alter the wavelength of the wave.
If the frequency is increased the wavelength will be decreased. Wavelength lambda and frequency f are connected by the speed c of the medium. c can be air = 343 m/s at 20 degrees celsius or water at 0 dgrees = 1450 m/s. c can be light waves or electromagnetic waves = 299 792 458 m/s. The formulas are: c = lambda x f f = c / lambda lambda = c / f
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
As the frequency goes up, the wavelength decreases. Their product is always the same number . . . the wave's speed.
If frequency is tripled, the wavelength will be one-third of its original value. This is because the speed of the wave remains constant, so as frequency increases, wavelength decreases to maintain a constant speed.
Frequency = Speed of Light / Wavelength.As you can see from this formula, when the wavelength increases the frequency decreases.For example, we will say that the standard wavelength is 5m.F = 3.0 x 108 / 5= 60,000,000 hertzSay if we increased the wavelength to 6m:F = 3.0 x 108 / 6= 50,000,000 hertzAs you can see, if we increase the wavelength, the frequency decreases.If we decreased the wavelength to 4m:F = 3.0 x 108 / 4= 75,000,000 hertzAs you can see, if we decrease the wavelength, the frequency decreases.
As wavelength increases the frequency decreases.