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Assuming gas is ideal and mass is conserved, solve for n:

P1V1/(RT)=n;

n=(3*24)/RT

Compressing the gas to a new volume and solving for P:

P2=nRT/V2

P2=(3*24)/RT * RT/16

P2 = 3*24/16

P2 = 4.5 ATM

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it should be 2

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5.3 liters

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Q: What happens to the pressure of a sample of a gas if its volume were changed from 6.0 L to 3.0 L?
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